Question

बहुपद के लिए x, (0) p(1) और p(2) ज्ञात कीजिए p(x) =(x-1) (x+1)
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Answer 1

$Given \: polynomial \: p(x) = (x-1)(x+1)$

$i) Value \: p(0) = ( 0-1)(0+1)$

$= (-1) \times 1$

$= -1$

$ii) Value \: p(1) = ( 1-1)(1+1)$

$= 0 \times 2$

$= 0$

$iii) Value \: p(2) = ( 2-1)(2+1)$

$= 1 \times 3$

$= 3$

•••♪

Answer 2

Answer:

-1

0

3

Step-by-step explanation:

$(x - 1)(x + 1)$

$value = x = 0$

$(0 - 1)(0 + 1)$

$- 1 \times 1$

$- 1$

$value = x = 1$

$(1 - 1)(1 + 1)$

$0 \times 2$

$0$

$value = x = 2$

$(2 - 1)(2 + 1)$

$1 \times 3$

$3$

OK

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