Question

बहुपद x2 -15x+56 का घात है​

Answer 1

Answer:

x²-15x+56=0

x²-7x-8x+56=0

x(x-7)-8(x-7)=0

(x-8)(x-7)=0

therefore. x-8=0. or. x-7=0

=> x=8 or x=7

Answer 2

Step-by-step explanation:

x²—15x+56

let :

x²—15x+56 = 0

x²—8x—7x+56=0

x(x—8)—7(x—8)=0

(x—7) (x—8) =0

x—7=0

x=7

x—8=0

x=8

I hope it will help you