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Answers
Explanation:
†Question−1
⠀⠀⠀⠀
Two times a number is equal to six less than three times the number what the number is.
❍ Let's say, the number be n respectively.
A/Q,
Two times a number is equal to six less than three times the number '(n)'.
Therefore,
↠ 2n = 3n – 6
↠ 2n - 3n = - 6
↠- n = - 6
(Cancelling –ve sign from both sides).
↠ n = 6
\therefore∴ Hence, the needed number is 6.
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\underline{\bf{\dag} \:\mathfrak{Question-2}}
†Question−2
⠀⠀⠀⠀
ABC is an isosceles triangle right angled at C. Prove that AB² = 2AC².
AnswEr :
Here, In ∆ ACB, we'll use Pythagoras theorem.
AC = BC Because, in isosceles triangle two sides are always equal and ∆ACB is an isosceles triangle.
And, AB is Hypotenuse (longest side).
↠(Hypotenuse)² = (Height)² + (Base)²
↠(AB)² = (AC)² + (BC)²
Here, in triangle (AC = BC). Hence, we can write AC instead of BC.
↠(AB)² = 2AC² ⠀⠀⠀⠀⠀⠀ ∴ (Hence, Proved!)