भाषा की ओर Sure निम्नलिखित वर्णों से समानार्थी और विरुद्धार्थी शब्दों की जोड़ियाँ ढूँढ़ो और अपने वाक्यों में प्रयोग करके कॉपी में लिखो: FIED पुष्प = फूल रात x दिन स-----करीब सब-x- बीब्त --X- ह स्तल अ ब मा न द ष्प मे उ द स छो डा. ज बा फू नी पा a a दि टा म्मा पु वा. p
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The chemical compound capsaicin (8-methyl-N-vanillyl-6-nonenamide) is the active component of chili peppers, which are plants belonging to the genus Capsicum.
Answer:
What is western music ???Given :-
→ \sf{n^{th}}nth term of the AP = 4n +5
To find :-
\sf{3^{rd}}3rd term of the AP
Solution :-
Let \sf{t_{n}}tn denote the \sf{n^{th}}nth term of the sequence
\sf{t_{n}= 4n + 5}tn=4n+5
So, first term = \sf{t_{1}}t1 \sf{= 4(1)+5 = 9}=4(1)+5=9
Second term = \sf{t_{2} = 4(2) + 5 = 13}t2=4(2)+5=13
Third term = \sf{t_{3} = 4(3) + 5 = 17 }t3=4(3)+5=17
\boxed{\sf{t_{3} = 17 }}t3=17
\bold{3^{rd} \ term \ of \ the \ AP = 17}3rd term of the AP=17
C 2. The n'" term of an arithmetic progression is a = 4n+ 5 then the 3rd term is : A. 5 B. 9 D. 17 C. 13Given :-
→ \sf{n^{th}}nth term of the AP = 4n +5
To find :-
\sf{3^{rd}}3rd term of the AP
Solution :-
Let \sf{t_{n}}tn denote the \sf{n^{th}}nth term of the sequence
\sf{t_{n}= 4n + 5}tn=4n+5
So, first term = \sf{t_{1}}t1 \sf{= 4(1)+5 = 9}=4(1)+5=9
Second term = \sf{t_{2} = 4(2) + 5 = 13}t2=4(2)+5=13
Third term = \sf{t_{3} = 4(3) + 5 = 17 }t3=4(3)+5=17
\boxed{\sf{t_{3} = 17 }}t3=17
\bold{3^{rd} \ term \ of \ the \ AP = 17}3rd term of the AP=17
Given :-
→ \sf{n^{th}}nth term of the AP = 4n +5
To find :-
\sf{3^{rd}}3rd term of the AP
Solution :-
Let \sf{t_{n}}tn denote the \sf{n^{th}}nth term of the sequence
\sf{t_{n}= 4n + 5}tn=4n+5
So, first term = \sf{t_{1}}t1 \sf{= 4(1)+5 = 9}=4(1)+5=9
Second term = \sf{t_{2} = 4(2) + 5 = 13}t2=4(2)+5=13
Third term = \sf{t_{3} = 4(3) + 5 = 17 }t3=4(3)+5=17
\boxed{\sf{t_{3} = 17 }}t3=17
\bold{3^{rd} \ term \ of \ the \ AP = 17}3rd term of the AP=17