Question

bhai jaldi se solution do iska step by step

Answer 1

Hi there!

Given poly. (a + 5)x² + 13x + 6a

Let $\alpha$ n' 1/ $\alpha$ be two zeroes of the polynomial.

Then,

$\alpha$ × 1/ $\alpha$ = c / a

1 = 6a / a + 5

6a = a + 5

6a - a = 5

5a = 5

a = 5/5 = 1

Hence,
Value of 'a' is 1

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Hope it helps!