bhai koi to esse rationalise kar do yaar . please
please do it fast.
I have asked this question 3 times but not got the answer.
Answers
Answer:
3+2−51=1232+23+30
Step-by-step explanation:
Given : Expression \frac{1}{\sqrt{3}+\sqrt{2}-\sqrt{5}}3+2−51
To find : Simplify the expression ?
Solution :
We can write expression as,
\frac{1}{(\sqrt{3}+\sqrt{2})-\sqrt{5}}(3+2)−51
Rationalize the denominator,
=\frac{1}{(\sqrt{3}+\sqrt{2})-\sqrt{5}}\times \frac{(\sqrt{3}+\sqrt{2})+\sqrt{5}}{(\sqrt{3}+\sqrt{2})+\sqrt{5}}=(3+2)−51×(3+2)+5(3+2)+5
=\frac{\sqrt{3}+\sqrt{2}+\sqrt{5}}{(\sqrt{3}+\sqrt{2})^2-(\sqrt{5})^2}=(3+2)2−(5)23+2+5
=\frac{\sqrt{3}+\sqrt{2}+\sqrt{5}}{3+2\sqrt6+2-5}=3+26+2−53+2+5
=\frac{\sqrt{3}+\sqrt{2}+\sqrt{5}}{2\sqrt6}=263+2+5
Multiply and divide by \sqrt66
=\frac{\sqrt{3}+\sqrt{2}+\sqrt{5}}{2\sqrt6}\times \frac{\sqrt6}{\sqrt6}=263+2+5×66
=\frac{\sqrt{18}+\sqrt{12}+\sqrt{30}}{2\times 6}=2×618+12+30
Step-by-step explanation:
refer to the above attachment