Question

bhai koi to esse rationalise kar do yaar . please
please do it fast.
I have asked this question 3 times but not got the answer.​

Answer 1

Answer:

3+2−51=1232+23+30

Step-by-step explanation:

Given : Expression  \frac{1}{\sqrt{3}+\sqrt{2}-\sqrt{5}}3+2−51

To find : Simplify the expression ?

Solution :

We can write expression as,

\frac{1}{(\sqrt{3}+\sqrt{2})-\sqrt{5}}(3+2)−51

Rationalize the denominator,

=\frac{1}{(\sqrt{3}+\sqrt{2})-\sqrt{5}}\times \frac{(\sqrt{3}+\sqrt{2})+\sqrt{5}}{(\sqrt{3}+\sqrt{2})+\sqrt{5}}=(3+2)−51×(3+2)+5(3+2)+5

=\frac{\sqrt{3}+\sqrt{2}+\sqrt{5}}{(\sqrt{3}+\sqrt{2})^2-(\sqrt{5})^2}=(3+2)2−(5)23+2+5

=\frac{\sqrt{3}+\sqrt{2}+\sqrt{5}}{3+2\sqrt6+2-5}=3+26+2−53+2+5

=\frac{\sqrt{3}+\sqrt{2}+\sqrt{5}}{2\sqrt6}=263+2+5

Multiply and divide by \sqrt66

=\frac{\sqrt{3}+\sqrt{2}+\sqrt{5}}{2\sqrt6}\times \frac{\sqrt6}{\sqrt6}=263+2+5×66

=\frac{\sqrt{18}+\sqrt{12}+\sqrt{30}}{2\times 6}=2×618+12+30

Answer 2

Step-by-step explanation:

refer to the above attachment