Question

bhai please koi ise solve kardo

Answer 1

alpha + beta + gama = -b/a
(a) + (a+b) +(a + 2b) = -(-6)/1
3a + 3b = 6
a + b = 2 (1)

(alpha)(beta)(gama) = -d / a
(a)(a+b)(a+2b) = -10/1
a^2 + 2ab + ab + 2b^2 = -10
a^2 + 3ab + 2b^2 = -10 ( 2)

from 1 a = 2 - b
(2-b)^2 + 3(2-b)b + 2b^2 = -10

4 + b^2 - 4b + 6b - 3b^2 + 2b^2 = -10

4 + 2b = -10
2b = - 10 - 4
b = -7

put val. of b in eq. 1

a + b = 2
a + ( -7) = 2
a = 9

So the value of a = 9 and b= -7

Hope its help you...
Best of luck for your tommorow exam☺