Question

bhai please krdo jldi factorise x⁸-y⁸​

Answer 1

$\huge{\underline{\sf{\blue{Answer:-}}}}$

= $\sf{{x}^{8}}$ - $\sf{{y}^{8}}$

= $\sf{({x}^{4} + {y}^{4})({x}^{4} - {y}^{4})}$

= $\sf{({x}^{2} + {y}^{2})({x}^{2} - {y}^{2})({x}^{4} + {y}^{4}) }$

= $\sf{( x + y) ( x - y)({x}^{2} + {y}^{2})({x}^{4} + {y}^{4}) }$

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Answer 2

ANSWER✔

$\sf\dashrightarrow x^8-y^8$

$\sf\implies (x^4+y^4)(x^4-y^4)$

$\sf\implies (x^4+y^4)(x^2+y^2)(x+y)(x-y)$

$\large{\boxed{\bf{ \star\:\: (x^4+y^4)(x^2+y^2)(x+y)(x-y)\:\: \star}}}$

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