bhaii yrr krdo koiii solve iise
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Hey...mate here is yur ans...
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⏩ 1) Acceleration a = F /( m + M )
⏩ 2) force exerted by rope T = Ma = M.F /( m + M )
⏩ 3) T1 = [ m / 2 + M ]a = [ m + 2M / 2 ] [ F / m+ M]
Tension in rope at mispoint T1 = (m + 2 M)F / 2(m + M)
______________________________
HOPE IT HELPS U✌
♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦
⏩ 1) Acceleration a = F /( m + M )
⏩ 2) force exerted by rope T = Ma = M.F /( m + M )
⏩ 3) T1 = [ m / 2 + M ]a = [ m + 2M / 2 ] [ F / m+ M]
Tension in rope at mispoint T1 = (m + 2 M)F / 2(m + M)
______________________________
HOPE IT HELPS U✌
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HI HERE IS THE ANSWER
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