Bhamsingh and sukhalal contested the assembly election. bhimsingh won the election by 2000 votes,securing 55% of the total votes. 10% of the total voters did not votes. 26. how maney votes were cast in favour of bhimsing?
Answers
Answered by
4
Let the total votes cast be x.
The votes to Bahmsingh = 0.55x
The votes to Sukhalal = 0.45x
0.55x = 0.45x + 2000
0.55x - 0.45x = 2000
0.1x = 2000
x = 20000
The total who cast their votes were 20000
=20000
= 20000 people
Those who voted for Bahmsingh are :
0.55 × 20000 = 11000
= 11000 voters.
Answered by
0
Answer:
Step-by-step explanation
Let the total number of votes cast be X
Votes Bhimsingh secured =55%X
Votes Sukhalal secured= 35%X
(10% did not vote so )
55%X=35%X+2000
0.55X=0.35X+2000
0.20X=2000
X=10000
VOTES IN FAVOUR OF BHIMSINGH= 55%X
=55%*10000
=5500
Similar questions