Question

Bharath bought a shirt for ₹336, including 12% sales tax and a necktie for₹110 including 10% sales tax. Find the printed price of shirt and necktie together

Answer 1

Answer:

Step-by-step explanation:

Printed price of shirt=336*100/112(take the price before the tax is added as 100 and after adding tax say the price is 112)

=₹300

Printed price of necktie=110*100/110(do the same)

=100

So.

,total=₹300+₹100=₹400

Hope it is helpful to u

Answer 2

Given that :

• Bharath bought a shirt for ₹336, including 12% sales tax.
• He also bought a necktie for₹110 including 10% sales tax.

To find :

• The print price of short and necktie together.

Solution :

Let the printed price of the shirt be ₹x.

Then, sales tax on the shirt

= ₹ $\sf \left(x \times \dfrac{12}{100}\right)$

= ₹ $\sf \dfrac{3x}{25}$

∴ Total cost of the shirt = ₹ $\bf \left(x + \dfrac{3x}{25}\right)$

= ₹ $\sf \dfrac{28x}{25}$

But, Cost of the shirt is given as ₹336.

$\implies \sf \frac{28x}{25} = 336 \\\\\implies \sf x = \left(336 \times \frac{25}{28}\right)\\\\ \implies \sf x =300$

Thus, the list price of shirt is ₹300.

Again,

Let the printed price of the necktie be ₹y.

Then, sales tax on the necktie

= ₹ $\sf \left(y \times \dfrac{10}{100}\right)$

= ₹ $\sf \dfrac{y}{10}$

∴ Total cost of the necktie = ₹ $\bf \left(y + \dfrac{y}{10}\right)$

= ₹ $\sf \dfrac{11y}{10}$

But, Cost of the necktie is given as ₹110.

$\implies \sf \frac{11y}{10} = 110 \\\\\implies \sf y = \left(110 \times \frac{10}{11}\right)\\\\ \implies \sf y =100$

Thus, the list price of the necktie is ₹100.

The total printed price of the shirt and the necktie = ₹ (300 + 100)

= ₹ 400

Hence, the answer is ₹ 400.