Question

Bhaskar and Shakuntala challenge each other in math and are at loggerheads always. At
the end of a milestone in their project, the team had dinner and were seated in a circular
table. If there were 16 people for dinner, what are the odds against the event that
Bhaskar and Shakuntala will sit together
12:3
13:2
17:3
3:17​

Answer 1

Step-by-step explanation:

12:3 is the answer for this

Answer 2

Answer:

The odds against Bhaskar and Shakuntala sitting together are 13:2

Step-by-step explanation:

The total number of arrangements - (16-1)!

Favourable chances Bhaskar and Shakuntala will sit together = $2!(16-2)!$

p=$\frac{2!(16-2)!}{(16-1)!} = \frac{2!*14!}{15!} = \frac{2}{15}$

The odd against = $\frac{1-p}{p}$ = $\frac{13}{2}$

So the odds against are 13:2