Question

Bhaskar in the form of a frustum of cone can hold 14245 CM square of water the radius of top and bottom of 14 cm and 10.5 CM respectively find the height of the basket​

Answer 1

Answer:

Volume of frustum of cone = volume of water in it

1/3*π[R^2+r^2+rR]*h=14245

1/3*22/7*[(10.5) ^2+(14) ^2+14*10.5]*h=14245

1/3*22/7*[110.25+196+147.5]*h=14245

1/3*22/7*453.75*h=14245

h=14245*7*3*100/22*45375

h=6.1 (approx)