Bhaskar went for hiking with scouts’ team and there the scouts were given a task to build tentswith the help of bamboos, ropes and canvas. The frame of the tent that Bhaskar prepared was of pyramid shape. To make it sturdier Bhaskar thought that he should fix a wooden stick on the triangular sides of the tent and fix the wooden stick at the mid points of the sides of two sides of the triangle. The distance between the end point of the bamboos on the sides was 3 m.Due to lack of even length bamboo sticks Bhaskar the triangles on the edges of tent were not congruent. Look into the figure of Bhaskar’s tent and answer the following questions. ( a ) To make tent sturdy Bhaskar used bamboo IJ in the back part of the tent. What length of bamboo shall he use so that it should be fixed exactly?
Answers
Answer:
Given :
Area of Rhombus is 32 cm² .
Length of one diagonal is 8 cm .
To Find :
Length of other Diagonal .
Solution :
\longmapsto\tt{{d}_{1}=8\:cm}⟼d
1
=8cm
Using Formula :
\longmapsto\tt\boxed{Area\:of\:Rhombus=\dfrac{1}{2}\times{{d}_{1}}\times{{d}_{2}}}⟼
AreaofRhombus=
2
1
×d
1
×d
2
Putting Values :
\longmapsto\tt{32=\dfrac{1}{{\not{2}}}\times{{\not{8}}}\times{{d}_{2}}}⟼32=
2
1
×
8×d
2
\longmapsto\tt{32=4\:{d}_{2}}⟼32=4d
2
\longmapsto\tt{{d}_{2}=\cancel\dfrac{32}{4}}⟼d
2
=
4
32
\longmapsto\tt\bf{{d}_{2}=8\:cm}⟼d
2
=8cm
So , The Length of other diagonal of the Rhombus is 8 cm .
____________________
VERIFICATION :
\longmapsto\tt{32=\dfrac{1}{2}\times{{d}_{1}}\times{{d}_{2}}}⟼32=
2
1
×d
1
×d
2
\longmapsto\tt\boxed{32=\dfrac{1}{2}\times{8}\times{8}}⟼
32=
2
1
×8×8
\longmapsto\tt{32=\cancel\dfrac{64}{2}}⟼32=
2
64
\longmapsto\tt\bf{32=32}⟼32=32
HENCE VERIFIED