Question

Bhavna's weight is 6kg more than Beena. sneha's weight is 8 kg less than double of beena's weight. If the sum of their weight is 98kg , find the weight of them​

Answer 1

Step-by-step explanation:

let beena weigh=x

weight of Bhawna=x+6

weight of Sneha=2x-8

sum of their weights=98kg

ATQ=

X+x+6+2x-8=98

x+x+2x+6-8=98

4x-2=98

4x=98+2

4x=100

X=100/4

x=25

therefore x=25

1. hence beena's weight=25kg
2. Bhavna weighs=25+6=31kg
3. snaha weighs=2×25-8=42kg

Answer 2

Answer:

Step-by-step explanation:

Let beenas weight to be x

Then bhavana weight be (x+6)

Sneha weight be (2x-8)

By given condition

X + (x+6) + (2x-8) = 98

4x-2=98

4x=98+2

4x=100

X=100/4

X=25

Therefore

Beenas weight is 25 years

Bhavana weight is 31

Sneha weight is 42