Bhawana took a pale green substance ‘A ‘ in test tube. And heated it
over the flame of a burner. A brown colored Residue ‘B’ was formed
along with the evolution of two gases with burning smell of Sulphur.
Identify A and B write the chemical reaction involved.
Answers
Answered by
66
A- FeSO4
B- Fe2O3
B- Fe2O3
feSO4 -----> Fe2O3 + SO2 + SO3
hope it helps:)
please mark as brainlies if it does..!!
Answered by
39
The substance A is ferrous sulphate . When it is heated ferric oxide ,sulphur trioxide and sulphur dioxide is formed . The colour of the gas sulphur trioxide is brown . Hence ,sulphur trioxide is B .
FeSO4-> Fe2O3 +SO2 +SO3
FeSO4-> Fe2O3 +SO2 +SO3
Similar questions