Question

Bheem is twice as old as Nobith
a five years ago his age was three times of Nobitha's age find the their present age

Answer 1

Let age of Nobith be X years.


Age of bheem = 2 × ( Age of Nobith ) = 2X years.



Five years ago age of Nobith = ( X - 5 ) years.


Five years ago age of bheem = ( 2X - 5 ) years.



According to the question,


2X - 5 = 3 ( X - 5 )


2X - 5 = 3X - 15



3X - 2X = -5 + 15



X = 10 years.


Present age of Nobith = X = 10 years.


and,

Present age of Bheem = 2X = 20 years.

Answer 2

Define their present age:

Let Nobith be x years old

Bheem will be 2x

Express their age 5 years ago:

Nobith = x - 5

Bheem = 2x - 5

Define equation and solve x:

5 years ago, Bheem was 3 times of Nobith's age

2x - 5 = 3 ( x - 5)

2x - 5 = 3x - 15

x = 10

Find their present age:

Nobith = x = 10 years old

Bheem = 2x = 10 x 2 = 20 years old

Nobith is 10 years old and Bheen is 20 years old