Bhor model three suborbit electron wave number??
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Answer :- Correct = 3
Angular momentum of nth bohr orbit = 2λ /nh
m.v.r n = 2λ / nh
mv= λ / h
(according to de Broglie)
( λ / h)r / n = 2λ / nh
nλ=2π r /n
(n=3)
2λ=2πr/n
these the circumference of 3 rd
Bohr orbit equal to 3 terms the wavelength of an electron makes this revolution around the 3 rd
orbit
Hence no. of the wave =3
HOPE THIS HELPS YOU !!
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