Math, asked by goldigupta77798, 7 months ago

Bhushan is now 9years older than Aanya. In 10years, Bhushan will be twice as old as Aanya was 10years ago. Find their present ages.​

Answers

Answered by Anonymous
6

Answer:

Let the present age of Aanya be ‘x’ years old. Then,

Bhushan's age = (x+ 9) years old.

After ten year's Bhushan's age would be (x + 9 + 10) years old.

= (x + 19) years old.

And Aanya age would be (x + 10) years old.

According to question,

x + 10 = 2(x - 10) \\  =  > (x + 19) = 2x - 20 \\  =  > 2x - x = 19 + 20 \\  =  > x = 39

Therefore, current Aanya's age = 39 years old.

Current Bhushan's age = x + 9 years old.

= 39 + 9

= 48 years old.

Answered by nishtha295
3

Answer:

Let the present age of B be x years. , 

Then, the present age of A would be (x+9) years.

After 10 years, the age of A would be (x+9+10)=(x+19) years and before then years, the age of B was (x−10) years. 

Now, from the information given in the question, 

(x+19)=2(x−10)

or x+19=2x−20 or x=19+20=39 years

Therefore, the present age of B is 39 years. 

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