Question

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Answer 1

Here is your answer in the attachment.

-100(0.732)
73.2 m

Answer 2

Refer the attachment for the figure.

Step by step explanation :

Let AB be the height of the light house.

Let the two ships be at C and D.

CD = Distance between two ships

Now,

In ∆ ABC,

tan 45° = AB / BC

( tan 45° = 1 )

1 = 100/BC

BC = 100 metres

Now, In ∆ ABD,

tan 30° = AB / BD

1/√3 = 100/( BC + CD )

1/√3 = 100/(100 + CD)

100 + CD = 100√3

CD = 100√3 - 100

CD = 100(√3 - 1)

CD = 100 ( 1.73 - 1 )

CD = 100 × 0.73

CD = 73 metres

Thus,

Distance between two ships is around 73 metres.

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