bicycle initially moving with a velocity of 5.0 ms-1 accelerates for 5s at the rate of 1ms-2. How much distance does it cover in 5s?
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Answer:
u = 5 m/s
a = 1 m/s²
t = 5s
Using the second equation of motion ,
S= ut + 1/2 at²
S = 5×5 + 1/2 ×1×5²
S = 25 + 25/2
S= 50+25/25
S= 75/2
S= 37.5m
Therefore the distance covered is 37.5m
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