Question

Big question but easy to understand What would be the value of 'g' on earths surface if its mass was twice -and its radium half of what it is now? mass of earth = 6*10^24; radius =6.4*10^6. please try to explain this sum in detail by solving it on your book by sending phto plzz try to answer in detail with photo<br />​

Answer 1

g=GM/R²

M'=2M

R=R/2

g'=GM'/R'²

=G*2M/R²/4

=8GM/R²

=8g

as g=9.8 m/s²

therefore

g'=8g

=8*9.8

=78.4 m/s²

hope this helps.