Question

biggest 5 digit num divisible by 39

Answer 1

Answer:

99999 is the largest 5 digit number. Dividing 99999 by 120, remainder=39. Subtract this remainder from the highest 5 digit number i.e. 99999-39=99960 is the number.

Step-by-step explanation:

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Answer 2

Answer:

The biggest 5-digit number that is divisible by 39 is 99996.

Explanation:

To find the biggest 5-digit number that is divisible by 39, we need to find the largest multiple of 39 that is less than or equal to 99999 (the largest 5-digit number).

The prime factors of 39 are 3 and 13. So, we need to find the largest multiple of 39 that can be expressed as the product of 3 and 13.

The largest multiple of 39 that is less than or equal to 99999 can be obtained by dividing 99999 by 39 and taking the floor value of the result. This is because the largest multiple of 39 that is less than or equal to 99999 is the product of 39 and the largest integer that is less than or equal to 99999/39.

So, we have:

99999 ÷ 39 = 2564.076923...

Taking the floor value of this result, we get:

2564

Therefore, the largest 5-digit number that is divisible by 39 is:

2564 x 39 = 99996

So, the biggest 5-digit number that is divisible by 39 is 99996.

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