Math, asked by vation, 1 year ago

Bina's monthly income is 90%of Anita's income. The total of both thir income is Mr Sen income .If Mr sen annual income is 775200 then what is the Bina's monthly income.

Answers

Answered by dhritimalpe24
2

Answer: HERE IS UR  ANSWER

RS.30600

Step-by-step explanation: Description for Correct answer:

Mr. Sen's monthly income = (Bina + Anita)'s monthly income  

=  

775200

12

=Rs.64600

77520012=Rs.64600

According to the question,  

Bina's monthly income = 90% of Anita's monthly income  

=>  

Bina

Anita

=

90

100

=

9

10

BinaAnita=90100=910

Bina's monthly income =  

9

19

×64600

919×64600

=> Bina : Anita = 9 : 10  

Bina's monthly salary = Rs.30600



vation: and what is Anita income
dhritimalpe24: its givin only beenas income to find anitas again its a long process
vation: ans ko kahan sai copy kiya
dhritimalpe24: solve kiya hain
vation: copy kiya hai
dhritimalpe24: nahi ge solve kiya hain
dhritimalpe24: it was the same question given in one of the reference books
vation: phir anita ki income bhi nikallo
Answered by nehu215
1

\huge \overline{ \underline{ \boxed{ \tt \pink {Question}}}}

\begin{gathered}\tt \red {The \: ratio \: of \: the \: income \: of \: [/tex]Arun} \\ \tt \red {and \: Bina \: is \: 3:4. \: If \: their \: total }\\ \tt \red{ income \: is ₹ 21,000, \: what \: are \: their } \\ \tt \red{ individual \: incomes}\end{gathered} [/tex]

The ratio of the income of arun

andBinais3:4.Iftheirtotal

incomeis₹21,000,whataretheir

individualincomes

\huge \overline{ \underline{ \boxed{ \tt \purple {Answer}}}}

Answer

\tt \dag Given \dag†Given†

\tt \green{ratio \: of \: the \: income \: of \: arun \: and \: bina \: is3 \ratio4}ratiooftheincomeofarunandbinais3:4

\tt \blue{sum \: of \: their \: income \: is \: rs.21000. }sumoftheirincomeisrs.21000.

\tt \dag Find \dag†Find†

\tt \purple{their \: individual \: income.}theirindividualincome.

\tt \dag Solution \dag†Solution†

\tt \orange{let \: the \: income \: of \: arun \: be \: 3x}lettheincomeofarunbe3x

\tt \gray{income \: of \: bina \: be \: 4x}incomeofbinabe4x</p><p></p><p>[tex]\mathbb{ ACCORDING \: TO \: QUESTION }ACCORDINGTOQUESTION</p><p></p><p>[tex]\tt \pink{income \: of \: arun + income \: of \: bina = rs.21000}incomeofarun+incomeofbina=rs.21000</p><p></p><p>[tex]\tt \green{3x + 4x = 21000}3x+4x=21000</p><p></p><p>[tex]\tt \red{7x = 21000}7x=21000</p><p></p><p>[tex]\tt \blue{x = \frac{ \cancel{21000}}{ \cancel7} = 3000}x= </p><p>7</p><p>	</p><p> </p><p>21000</p><p> </p><p>	</p><p> =3000</p><p></p><p>[tex]\tt \purple{x = 3000}x=3000</p><p></p><p>[tex]\tt \green {Individual \: income \: of \: arun = 3x = 3 \times 3000 = \boxed{ \tt rs.9000} }Individualincomeofarun=3x=3×3000= </p><p>rs.9000</p><p>	</p><p> </p><p></p><p>[tex]\tt \gray {Individual \: income \: of \: bina = 4x = 4 \times 3000 = \boxed{ \tt rs.12000} }Individualincomeofbina=4x=4×3000=

rs.12000

Similar questions