Question

binding energy of a satellite is numerically equal to ,,,,,,,

2 points

potential energy

kinetic energy

total energy​

Answer 1

Answer:

Circular orbits arise whenever the gravitational force on a satellite equals the centripetal force needed to move it with uniform circular motion.

Fc = Fg

mv2 = Gm1m2

rp rp2

v2 = Gm1

r

Substitute this expression into the formula for kinetic energy.

K = ½m2v2

K = ½m2 ⎛

⎜

⎝ Gm1 ⎞

⎟

⎠

r

K = ½ Gm1m2

r

Note how similar this new formula is to the gravitational potential energy formula.

K = + ½ Gm1m2

r

Ug = − Gm1m2

r

K = −½Ug

The kinetic energy of a satellite in a circular orbit is half its gravitational energy and is positive instead of negative. When U and K are combined, their total is half the gravitational potential energy.

E = K + Ug

E = −½Ug + Ug

E = ½Ug

E = − Gm1m2

2r

The gravitational field of a planet or star is like a well. The kinetic energy of a satellite in orbit or a person on the surface sets the limit as to how high they can "climb" out of the well. A satellite in a circular orbit is halfway out (or halfway in, for you pessimists).

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Answer 2

Answer:

the answer to this question is B) Kinetic energy

Explanation:

KE = GMm/2r

BE = - TE = -(-GMm/2r) = GMm/2r