Question

Bindu(3,4) and (x, 1) mul bindu se samdursth hai to x=?

Answer 1

Answer:

x = $2\sqrt{6}$

Step-by-step explanation:

We have two points (3 , 4) and (x, 1)

Let A ≡ (3, 4)

B ≡ (x, 1)

Using Formula :-

Distance between two points M ≡ (a, b) and N ≡ (c ,d)

MN = $\sqrt{(a -c)^{2} + (b - d)^{2}$

So OA = $\sqrt{(3-0)^{2} + (4 - 0)^{2}$

OA = $\sqrt{3^{2}+4^{2}  }$

OA = $\sqrt{9+16}$

     = $\sqrt{25}$

OA = 5

Similarly OB = $\sqrt{(x-0)^{2}+(1-0)^{2}$

              OB = $\sqrt{x^{2}+1^{2}$

              OB = $\sqrt{x^{2}+1 }$

Beacuse OA and OB are equidistant then -

OA = OB

5 = $\sqrt{x^{2}+1 }$

Squaring on both sides-

$5^{2}$ = $x^{2} + 1$

25 = $x^{2} + 1$

24 = $x^{2}$

x = $\sqrt{24}$

x = $2\sqrt{6}$