Question

Birds stood on the swamp and ate frogs. Herons stood on one leg, and cranes stood on two legs. Each bird eat a frog, and the hunter counted 18 bird legs. How many Herons were there if the no. of frogs in lake decreased by 14? there was 14 less frogs in the lake?

Answer 1

Answer:

number of cranes are 4 and Herons are 10

Step-by-step explanation:

Let number of cranes be x

and,number of Heromnes be y

now , 2x+y=18...(i) (that's total number of legs)

and, x+y=14 (that's number of fishes reduced from pond)

mutiplying 2nd equation by 2 we get

2x+2y=28 .......(ii)

substracting eqn (i) from (ii)

we get y=10 now putting y in any of quations we can find x to be 4

Thanks for the question......

Answer 2

Given: Birds stood on the swamp and ate frogs. Herons stood on one leg, and cranes stood on two legs. Each bird eat a frog, and the hunter counted 18 bird legs.

To find: the number of herons in the lake.

Solution:

Let the number of cranes be x, and,number of Herones be y.

Understand that from the given question,

Total number of legs is,

$2x+y=18------(i)$  

and,

Total number of fishes reduced from the pond is,

$x+y=14------(ii)$

Multiply equation (ii) by 2.  

$2x+2y=28 ------(iii)$

Substract eqn (i) from (iii).

$\[\begin{array}{l}\,\,\,\,\,\,\,2x + 2y = 28\\\left( - \right)2x + \,\,\,y = 18\\\underline {\,\,\,\,\,\,\,\left( - \right)\,\,\,\,\,\left( - \right)\,\,\,\,\left( - \right)} \\\underline {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,y = 10\,\,\,} \end{array}\]$

Hence, the number of herons in the lake is 10.