Birr 300 is invested at 6 simple interest per annum. How long will it
take for the interest to amonut Birr 180?
Answers
Answer:
If P denotes the principal ($), R denotes the rate (percentage p.a.) and T denotes time (years), then:-
S.I = (P × R × T)/100
R = (S.I × 100)/(P × T)
P = (S.I × 100)/(R × T)
T = (S.I × 100)/(P × R)
If the denotes the amount, then A = P + S.I
Note:
● When we calculated the time period between two dates, we do not could the day on which money is deposited but we count the day on which money is retuned.
● Time is always taken according to the per cent rat.
● For converting time in days into years, divide th number of days by 365 (for ordering or lap year.)
● For converting time in month into years, divide th number of month by 12 (for ordering or lap year.)
Step-by-step explanation:
$ 900 for 3 years 4 months at 5% per annum. Find the amount also.
Solution:
P = $ 900,
R = 5% p.a.
T = 3 years 4 months = 40/12 years = 10/3 years
Therefore, S.I = (P × R × T)/100 = (900 × 5 × 10)/(100 × 3) = $ 150
Amount = P + S.I = $ 900 + $ 150 = $ 1050
(b) $ 1000 for 6 months at 4% per annum. Find the amount also.
Solution:
P = $ 1000,
R = 4% p.a.
T = 6 months = 6/12 years
S.I = (P × R × T)/100 = (1000 × 4 × 1)/(100 × 2) = $ 20
Therefore, A = P + I = $( 1000 + 20) = $ 1020
(c) $ 5000 for 146 days at 15¹/₂% per annum.
Solution:
P = $ 5000, R = 151/2% p.a. T = 146 days
S.I = ( 5000 × 31 × 146)/(100 × 2 × 365)
= $ 10 × 31 = $ 310
(d) $ 1200 from 9ᵗʰ April to 21ˢᵗ June at 10% per annum.
Solution:
P = $ 1200, R = 10% p.a. T = 9th April to 21st June
= 73 days [April = 21, May = 31, Jun = 21, 73 days]
= 73/365 years
S.I = (1200 × 10 × 73)/(100 × 365) = $ 24
Step-by-step explanation:
P=300
R=6%
I=180
So, P×R×T/100=I
=300×6×T/100=180
=18T=180
=T=10 year
Hence, the time period is 10 year
Hope you get it
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