Biscuits occupy 7/8 th of the volume of their packet. The remaining 1/8 is unused. It is decided to re-design the packet so that the amount of unused space becomes 1/7. What fraction of the packet will the biscuits take up now? What fraction of unused space is increased? please answer.
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Answer:
6/7 or 12/14,1/56
Step-by-step explanation:
fraction of the packet the biscuit occupies⇒6/7 which is equal to 12/14
fraction of unused space increased⇒new value-initial value⇔1/7-1/8
which gives the final result as 1/56.
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