Question

Biscuits occupy 7/8 th of the volume of their packet. The remaining 1/8 is unused. It is decided to re-design the packet so that the amount of unused space becomes 1/7. What fraction of the packet will the biscuits take up now? What fraction of unused space is increased? Please read the question properly and then answer.

Answer 1

Answer:

The fraction of the new pack with biscuit is 0.925 which is equivalent to \frac{37}{40}

40/37

Step-by-step explanation:

We are given that the unused fraction of the pack is \frac{1}{8}

8

1

In the redesign, the unused fraction is reduced by 40%

This means that:

new unused fraction = \frac{1}{8} - 0.4(\frac{1}{8} ) = \frac{1}{8} - \frac{1}{20} = \frac{3}{40} = 0.075

8

1

−0.4(

8

1

)=

8

1

−

20

1

=

40

3

=0.075

We know that the whole pack is equivalent to 100% which can be written as 1

Since 0.075 of the redesigned pack is empty, therefore:

new used fraction = 1 - 0.075 = 0.925 = \frac{37}{40}

40

37

Hope this helps :)

Answer 2

Answer:

0.925

Step-by-step explanation:

40/37

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