Bisecters of two concussive angles of a parallelogram intersect each other at?
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As ABCD is a parallelogram
 AD||BC and AB is a transversal.
 DAB + ABC = 180o [Angles on the same side of transversal]

1 + 2 = 90o
In AOB ,1 + 2 + AOB = 180o
90o + AOB = 180o
AOB = 90o
Therefore, the bisectors of any two consecutive angles of parallelogram intersect at right angles.
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