Question

bisecting the hypotenuse,
A right angled triangle has vertices (1, 1), (1,7) and (7, 1). Prove that the mid-point of
hypotenuse lies at equal distance from each vertex,​

Answer 1

Answer:

the circumcentre of the right angle triangle is at the midpoint of the hypotenuse

so,it is equidistant from all vertices of the triangle