Question

Bisectors of angle B and angle C of a triangle ABC intersect each other at the point O.

Prove that angle BOC = 900

+ ½ angle A​

Answer 1

Answer:

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Answer 2

Answer:

Now think in triangle BOC,

we have three angles, OBC, BOC and OCB

OBC = (B/2)

OCB = (C/2)

Let BOC = X

So, X + (B/2) + (C/2) = 180

From equation (1)

X + 90 - (A/2) = 180

X = 90 + A/2 (Proved !!!)

Step-by-step explanation:

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