Bisectors of angles A b and c of a triangle ABC intersect its circumcircle at point d e and f respectively prove that the angle of the triangle DEF are 90 degree-A/2, 90 degree-B/2 and 90 degree-C/2. Solve this problem by statement and reason format.
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Bisectors of angles A,B and C of a triangle ABC intersect its circumcircle at D,E and F respectively. Prove that the angles of the triangles DEF are 90o−21A, 90o−21B and 90o−21C.
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In △DEF,
∠D=∠EDF
But ∠EDF=∠EDA+∠FDA ....angle addition property
Now, ∠EDA=∠EBA and ∠FDA=∠FCA .....Angles inscribed in the same arc
∴∠EDF=∠EBA+∠FCA
=21∠B+21∠C
[Since BE is bisector of ∠B and CF is bisector ∠C]
∴∠D=2∠B+∠C ....(1)
Similarly, ∠E=2∠C+∠A and ∠F=2∠A+∠B ...(2)
Now, ∠A+∠B+∠C=180o ....angle sum
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