Bisectors of∠ B and ∠C of ∆ ABC intersect each other in point X.
Line AX intersects side BC in point Y.
AB = 5, AC = 4, BC = 6 then find AX/ XY.
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Asked on December 27, 2019 by
Amita Sankhla
In the figure, bisectors of ∠B and ∠C of ΔABC intersect each other in point X. Line AX intersects side BC in point Y. AB=5, AC=4, BC=6, then find
XY
AX
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Since, the bisectors of a triangle are concurrent, then AY is the bisector of ∠A.
Then from angle-bisector property we get, [Using the bisector of ∠C ]
XY
AX
=
YC
AC
........(1).
Again, since AY is the bisector of ∠A then
YC
BY
=
AC
AB
or,
YC
BY
=
4
5
or,
YC
BY+YC
=
4
5+4
or,
YC
BC
=
4
9
or, YC=
3
8
.
From (1) we get,
XY
AX
=
2
3
.
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