Bisectors of opposite angles of a cyclic quadrilateral PORS
intersect the circle, circumscribing it at the points A and B. If the
radius of the circle is 12 cm, then length of AB is
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Given:ABCD is a cyclic quadrilateral.
DP and QB are the bisectors of ∠D and ∠B, respectively.
To prove: PQ is the diameter of a circle.
Proof: Since,ABCD is a cyclic quadrilateral.
∴∠CDA+∠CBA=180∘ since sum of opposite angles of cyclic quadrilateral is 180∘
21∠CDA+21∠CBA=21×180∘=90∘
⇒∠1+∠2=90∘ ........(1)
But ∠2=∠3 (angles in the same segment QC are equal) ........(2)
⇒∠1+∠3=90∘
From eqns(1) and (2),
∠PDQ=90∘
Hence,PQ is a diameter of a circle, because diameter of the circle subtends a right angle at the circumference of the circle.
answer by swati
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