Question

Bittu starts his car from rest from his house with acceleration of 6 m/s^2 .If he took 7 second to reach his destiny .Calculate the distance of destiny from his house .

Answer 1

QUESTION:-

Bittu starts his car from rest from his house with acceleration of 6 m/s^2 .If he took 7 second to reach his destiny .Calculate the distance of destiny from his house .

EXPLANATION:-

u=0 m/s

a=6 m/s²

t=6 s

S= ??

To calculate the distance we gonna be using 2nd equation of kinematics:-

S=ut+(0.5)at²

Putting values;-

S=0×5+(0.5)(6)(7)²

S=3×7²

S=147 m

So the distance is 147 m,

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Answer 2

Question

Bittu starts his car from rest from his house with an acceleration of 6 m/s². If he took 7 seconds to reach his destiny. Calculate the distance of destiny from his house.

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Answer

Initial Velocity (u) = 0 m/s

Acceleration (a) = 6 m/s²

Time (t) = 7 sec

Distance (s) = ?

To find the distance covered, we'll apply the 2nd Equation of Motion.

2nd Equation of Motion → $s = ut + \dfrac{1}{2}at^{2}$

Substitute the values of variables from the equation and find the value of 's'.

$\implies s = 0(7) + \dfrac{1}{2}(6)(7)^{2}$

$\implies s = 0 + 3 \times 49$

$\implies s = 147 \ m$

∴ The distance of destiny from Bittu's house was 147 m.

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Additional Information

Acceleration is the rate of change of velocity in a given time period.

We have 3 Equations of Motion. They are -:

• 1st Equation of Motion -: v = u + at
• 2nd Equation of Motion -: s = ut + 1/2 at²
• 3rd Equation of Motion -: v² - u² = 2as

Here,

• 'u' stands for Initial Velocity
• 'v' stands for Final Velocity
• 't' stands for Time
• 'a' stands for Acceleration
• 's' stands for Distance

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