Bl and cm are medians of triangle abc right angled at a
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Answer:
Step-by-step explanation:
Given : ABC right angle triangle at A where BL and CM are the medians
To prove : 4(BL^2 + CM^2)=5BC^2
Proof :
Since BL is the median
AL=CL=1/2 AC .............(1)
Similarly CM is the median
AM = MB = 1/2 AB ........... (2)
In triangle ABC
BC^2 = AB^2 + AC^2
In triangle BAL
BL^2 =AB^2 +AL^2
BL^2 =AB^2 +(AC/2)^2
On further little solving steps
4BL^2 =4AB^2 +AC^2
Then in triangle MAC
CM^2 =AM^2 +AC^2
Doing same process here
We get
4CM^2 =AB^2 +4AC^2
Dear please refer next part of answer in pic which is up made for you
Hope it helps you..............!!
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