Question

•blater has refractive index = 1:33 & aur has refractive
index = 1.) Find the critical angle for
a water - air boundary​

Answer 1

Answer:

48.75°

Explanation:

Critical angle =

${ \sin}^{ - 1} ( \frac{refractive \: index \: of \: air}{refractive \: \: index \: of \: water} ) \\ = { \sin }^{ - 1} ( \frac{1}{1.33} )$

= 48.75°