Math, asked by sanjukumari29, 7 months ago

ble 13: A wire is in the form of a circle of radius 35 m. It is now bent in the form of a
equilateral triangle. Find the sides of triangle.​

Answers

Answered by ssasreeja
1

Answer:

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Answered by parul4747
1

Step-by-step explanation:

SOLUTION :

Given :

The radius of the circle = 35 m

According to the question,

The wire is bent in equilateral triangle

equilateral triangle :

The triangle whose all sides are equal and all the three angles are 60 degree each.

To be found :

The side of the triangle

So,

as we know that,

Circumference of circle = 2πr

[in which r is the radius of the circle]

So,

Circumference of circle = 2 ×22/7

now,

as the wire was bent to form triangle,

therefore,

the circumference of circle = the perimeter of equilateral triangle

Let one side of an equilateral triangle be x

Perimeter of triangle = 3x

Now,

⇒ 3x = 220m

⇒ x = 220 ÷ 3

⇒ x = 73.33 m

Hence,

The each side of an equilateral triangle is 73.33 m

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