Question

Bleas help me friends. don't give wrong Answer.​

Answer 1

Step-by-step explanation:

$[ \frac{1}{2} {x}^{2} + \frac{2}{3} {y}^{2} ]^{2} - [\frac{1}{2} {x}^{2} - \frac{2}{3} {y}^{2}]^{2}$

$[\scriptsize( \frac{1}{2 } {x}^{2})^{2} + \cancel2 \times \frac{1}{ \cancel2} {x}^{2} \times \frac{2}{3} {y}^{2} + ( \frac{2}{3} {y}^{2} )^{2}] - [ (\frac{1}{2} {x}^{2} )^{2} - \cancel2 \times \frac{1}{ \cancel2} {x}^{2} \times \frac{2}{3} {y}^{2} + (\frac{2}{3} {y}^{2})^{2}]$

$\scriptsize[ \frac{1}{4} {x}^{4} + \frac{2}{3} {x}^{2} {y}^{2} + \frac{4}{9} {x}^{4} ] - [ \frac{1}{4} {x}^{4} - \frac{2}{3} {x}^{2} {y}^{2} + \frac{4}{9} {y}^{4} ]$

$\scriptsize\frac{1}{4} {x}^{4} + \frac{2}{3} {x}^{2} {y}^{2} + \frac{4}{9} {x}^{4} - \frac{1}{4} {x}^{4} + \frac{2}{3} {x}^{2} {y}^{2} - \frac{4}{9} {y}^{4}$

$\scriptsize\frac{1}{4} {x}^{4} - \frac{1}{4} {x}^{4} + \frac{2}{3} {x}^{2} {y}^{2} + \frac{2}{3} {x}^{2} {y}^{2} - \frac{4}{9} {y}^{4} + \frac{4}{9} {x}^{4}$

$\frac{2 {x}^{2} {y}^{2} + 2 {x}^{2} {y}^{2} }{3}$

$\frac{4 {x}^{2} {y}^{2} }{3}$

I hope it is helpful

Answer 2

Answer:

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