Physics, asked by MayankBansal9585, 11 months ago

Block a and mass 2 kg is placed over block b of mass 8 kg. The combination is placed over a rough horizontal surface. Coefficient of friction between b and the floor is 0.5. Coefficient of friction between a and b is 0.4 horizontal force of 10 n is applied on block b. The force of friction between a and b is :

Answers

Answered by sohanq8
5

Answer:

8N

Explanation:

N - coefficient of friction between a and b

F = Nmg = 0.4 x 2 x I0 = 8N

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