Question

Block a has a mass of 2 kg and block b has 20 kg.if the coefficient of kinetic friction between block b and the horizontal surface is 0.1 and b is accelerating towards the right with a=2m/s^,then the mass of block c will be

Answer 1

Answer:

10.5 kg

Explanation:

Given a=2m/s²

M(of A)=2Kg

M(of B)=20Kg

μ(kinetic)=0.1

M(of C)=x

From free body diagram of C

T₂=x*g - x*a

T₂=8x

From free body diagram of A

T₁=M(of A)*g + M(of A)*a = 2*10 + 2*2

T₁=24

Free Body Diagram of B

T₂ - F(force due to kinetic friction) - T₁=M(of B)*a

=> 8x -μ*m*g - 24 = 20*2

=>8x - 0.1*20*10 - 24 = 40

=>8x = 84

=>x=84/8=10.5

ie. Mass of C is 10.5kg

Answer 2

Answer:

10.5kg

hope this will help you