Block a has a mass of 2 kg and block b has 20 kg.if the coefficient of kinetic friction between block b and the horizontal surface is 0.1 and b is accelerating towards the right with a=2m/s^,then the mass of block c will be
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48
Answer:
10.5 kg
Explanation:
Given a=2m/s²
M(of A)=2Kg
M(of B)=20Kg
μ(kinetic)=0.1
M(of C)=x
From free body diagram of C
T₂=x*g - x*a
T₂=8x
From free body diagram of A
T₁=M(of A)*g + M(of A)*a = 2*10 + 2*2
T₁=24
Free Body Diagram of B
T₂ - F(force due to kinetic friction) - T₁=M(of B)*a
=> 8x -μ*m*g - 24 = 20*2
=>8x - 0.1*20*10 - 24 = 40
=>8x = 84
=>x=84/8=10.5
ie. Mass of C is 10.5kg
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Answered by
9
Answer:
10.5kg
hope this will help you
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