Question

Block A has mass 1.00 kg and block B has mass 3.00kg.The
blocks collide and stick together on a level,frictionless surface.
After the collision,the kinetic energy (KE) of block A is
A.1/9th KE of block B
B.1/3th KE of block B
C.3 times the KE of block B
D.9 times the KE of block B
E.the same as the KE of block B Need explanation plz?​

Answer 1

ans:B

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Answer 2

B. Block A has mass 1.00 kg and block B has mass 3.00kg.The blocks collide and stick together on a level, frictionless surface. After the collision, the kinetic energy (KE) of block A is  $\frac{1}{3}$ KE of block B

• Since it is a frictionless surface the collision is elastic.
• In elastic collision momentum and kinetic energy remains conserved and thus there is no change in kinetic energy of the body after the collision.
• Since masses are directly proportional to kinetic energies and mass of B is thrice the mass of A.
• Therefore, after the collision kinetic energy of block A is $\frac{1}{3}$ KE of block B.