Block A in the figure has a mass of 1 kg and block B has a
mass of 2 kg. The blocks are forced together compressing a
massless spring between them and the system is released from
rest on a level frictionless surface. The spring is not fastened to
either of the blocks, when spring regains its natural length,
block B acquired a speed of 0.5 m/s. How much potential
energy was stored in the compressed spring?
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Answer:
0.75
m1v1=m2v2
1×v1= 2×0.5
V1 =1
_1_ ×(m1v1² +m2v2²) = 0.75
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