Question

Block A is moving horizontally with speed 5 m/sec, then the speed of block B at the
given instant is

(A) 3 m/sec
(B) 4 m/sec
(C) 2.4 m/sec
(D) 5 m/sec​

Answer 1

Answer:

So your Final ans is 3 m/sec  i m explaining u in other way..

Explanation:

given

Mass=m,Velocity=5m/s,d=2m,μ=0.25,g=10m/s  2

So for the mass 1, V in

=5m/s​  Let the final velocity that is imparted to the other mass before the collision be V  of

So Acceleration =μ×g=0.25×10=2.5⇒a=−2.5m/s  

2

(negative sign shows friction acts opposite to the direction of motion)

Now,

 V  of 2

=V  in 2

​  

+2as⇒V  of 2

​  

=25−2×2.5×2=15⇒V  

f15

​  

m/s

At the time of collision, momentum will be conserved. So the velocity of both mass will exchange.

For the second mass,

Velocity gained V  of = 15

m.s= to the initial velocity of the second mass= u

Now, A/C to the question the mass cofinal velocity of the second mass to rest sov=0

Thus, By the kinematic equations  

V  

2

=U  

2

+2as⇒==(  

15

​  

)  

2

+2×(−2.5)×s⇒s=  

5

15

Ans =3m

I hope its Helpful.

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