Block A of mass 4kg is to be kept at rest against a smooth vertical wall by applying a force F as shown in figure.the force required is??
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276
The vertical component of force should be equal to wieght of the object
FSin45 = mg
F/√2 = 4×10
F = 40√2 N
Force required is 40√2 N
FSin45 = mg
F/√2 = 4×10
F = 40√2 N
Force required is 40√2 N
Answered by
87
"According to the given details, the block A of mass 4kg is to be kept at rest against a smooth vertical wall by applying a force F.
Then the required force is calculated below. In fact, the vertical aspect of force is equal to the weight of an object. It is given as mg= FSin45.
F/√2 = 4×10
F = 40√2 N
Hence, the required force is 40√2 N.
"
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