Question

block A of mass M in the system shown in the f slides down the incline at a constant speed the coefficient of friction between block A and the surface is 1 ​

Answer 1

Answer:

Correct option is

B

M/3

Given,

Block A moving with constant velocity, mean net force on block A is zero

Force equilibrium on block A

F−F

r

−T=0

Where,

F(force due to garavity component)=Mgsinθ

F

r

(Friction force)=μ Mgcosθ

T(tension in cable)=weigth of block B=M

B

g

Mgsin30

o

−μMgcos30

o

−M

B

g=0

M

2

1

−

3

3

1

M

2

3

=M

B

M

B

=

3

M

Mass of block B is

3

M