Question

Block B is kept on block A in a symmetrical way. Two light ropes P and Q are supporting block A in a symmetrical
manner. System is stationary. Find tension in each rope.​

Answer 1

Solution :

Let g = 10 m/sec

Weight of block (A) = mg = 100×10 = 1000 N

Weight of block (B) = mg = 600 N

Net weight of blocks 1600N

$\sum f(x) \: =\:T_{2x}\: - \: T_{1x}$

$0 \: =\: T_{2x}\:-\:T_{1x}$

$T_{2x}\: =\: T_1x$

$T_2Cos\theta\: =\: T_1Cos\phi$

$\theta \: =\: \phi\: =\: 37^{\circ}$

$T_2\: =\: T_1$

Net forces Fy

$\sum Fy \: =\: T_{1y}\: +\: T_{2y}\: -\: W$

$0 \: =\: T_{1y}\: +\: T_{2y}\: -\: W$

$W \: =\: T_{1y}\: +\: T_{2y}$

$W \: =\: T_{1} Sin\theta \: +\: T_{2} Sin\phi$

$W \: =\: T_{1} Sin37^{\circ}\: +\: T_{2} Sin 37^{\circ}$

We got, $T_2\: =\: T_1$

$W \: =\: T_{2} Sin37^{\circ}\: +\: T_{2} Sin 37^{\circ}$

$1600 \: =\: 2 T_{2} Sin37^{\circ}$

$\dfrac{1600}{2.Sin37^{\circ}} \: =\: T_{2}$

$T_{2} \: =\: \dfrac{1600}{2.Sin37^{\circ}}$

$T_2\: =\: T_1\: =\: 1333.3 N$

Answer

Tension in Rope P & Q are equal to 1333.33 N.

Answer 2

Answer:

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