Physics, asked by pandu9811, 1 month ago

Block C is moving up at the constant speed of 6 in/s. Given that the elevations of blocks A and B are always equal, determine the velocity of B.

Answers

Answered by harshinireddyAnnadi
3

Answer:

4 in/s

hope this answer may help you

Explanation:

Answered by mithun890
0

Answer:

The velocity of B is 4in/s.

Figure is not given in the question no problem i will drop it.

Explanation:

  • when block C moves up, its makes an change in length of the rope, as shown in below figure.
  • By that cause, rope length of both block A & B changes.
  • lets, take 'x' be the change in length of rope for both  blocks A&B
  • C = A+B ( in terms of length, the change in C = both A and B)
  • by using basic formula , we can find the change in length of rope of block C,

                        distance = velocity x time

       for C, we know v & t,

               distance = 6 x 1 (seconds)

                             = 6.

  • for B, we know it is free at both ends therefore rope displaced twice  it is '2X'.
  • for A, we know it is fixed at one end and it can displace once, therefore it is 'X'.
  • lets find value of X, change in length of C = change in A&B,

                             C = A + B

                             6 = X + 2X

                            3X= 6

                              X=2.

  • now, we know the value of X = 2, lets find the velocity of block B,

                    distance = velocity x time

                          2X = velocity x 1 (we have to calculate per second )

                         2(2) = velocity

                   velocity = 4in/s.

Hence he velocity of block B is 4in/s.

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